What is the full load current for a 5 ohm, 20 watt resistor?

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Multiple Choice

What is the full load current for a 5 ohm, 20 watt resistor?

Explanation:
To find the full load current for a 5 ohm, 20 watt resistor, you can use the relationship between power (P), voltage (V), and current (I) in electrical circuits. The formulas that are relevant here are: 1. Power (P) = Voltage (V) × Current (I) 2. Ohm's Law: Voltage (V) = Current (I) × Resistance (R) From the first formula, we can express current in terms of power and voltage: I = P / V Since P = I² × R according to the rearrangement of the second formula, we can substitute to find current directly: I² = P / R Thus, to find the current, you can rearrange it as: I = √(P / R) Now plug in the values for power and resistance: 1. Power (P) = 20 watts 2. Resistance (R) = 5 ohms Calculating the current: I = √(20 / 5) I = √(4) I = 2 amperes This means that the full load current for this 5 ohm, 20 watt resistor is indeed 2 amperes. This matches the

To find the full load current for a 5 ohm, 20 watt resistor, you can use the relationship between power (P), voltage (V), and current (I) in electrical circuits. The formulas that are relevant here are:

  1. Power (P) = Voltage (V) × Current (I)
  1. Ohm's Law: Voltage (V) = Current (I) × Resistance (R)

From the first formula, we can express current in terms of power and voltage:

I = P / V

Since P = I² × R according to the rearrangement of the second formula, we can substitute to find current directly:

I² = P / R

Thus, to find the current, you can rearrange it as:

I = √(P / R)

Now plug in the values for power and resistance:

  1. Power (P) = 20 watts

  2. Resistance (R) = 5 ohms

Calculating the current:

I = √(20 / 5)

I = √(4)

I = 2 amperes

This means that the full load current for this 5 ohm, 20 watt resistor is indeed 2 amperes. This matches the

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